In this news, we discuss the IPL 13: MI win toss, opt to bat first against KXIP.
The Mumbai Indians won the draw and chose to beat Kings XI Punjab (KXIP) in the Indian Premier League (IPL) first here on Sunday. The Mumbai Indians are in phenomenal form as the team have won all of their previous five games and will look to extend their winning streak. The team led by Rohit Sham holds second place in the points table with 12 points, only behind the Delhi Capitals.
KXIP, on the other hand, has won just two of its eight matches and is placed at the bottom of the points table with just four points. However, the team had a brilliant eight-wicket victory over the Royal Challengers Bangalore in the previous game and will aim to deliver a similar performance against the Mumbai Indians. Neither team changed their game XI.
Kings XI Punjab playing XI: KL Rahul (w / c), Mayank Agarwal, Chris Gayle, Nicholas Pooran, Glenn Maxwell, Deepak Hooda, Chris Jordan, Murugan Ashwin, Mohammed Shami, Ravi Bishnoi, Arshdeep Singh; Mumbai Indians playing XI: Rohit Sharma (c), Quinton de Kock (w), Suryakumar Yadav, Ishan Kishan, Hardik Pandya, Kieron Pollard, Krunal Pandya, Nathan Coulter-Nile, Rahul Chahar, Trent Boult, Jasprit Bumrah. (ANI)
- The Mumbai Indians won the draw and chose to beat Kings XI Punjab (KXIP) in the Indian Premier League (IPL) first here on Sunday.
- IPL 13: MI wins in the toss, choose to beat KXIP first